The area of this circle is 42 π m2. what is the area of a 60° sector of this circle. this is just to help people :)
Accepted Solution
A:
Answer:The Area of sector is 7 [tex]\pi[/tex] m²Step-by-step explanation:Given as , for a circle :The Area of circle = 42 [tex]\pi[/tex] m²The angle of sector = Ф = 60°∵ Area of circle = [tex]\pi[/tex] × r² , where r is the radius of circleor, 42 [tex]\pi[/tex] m² = [tex]\pi[/tex] × r² ∴ r² = 42Now, Area of sector = [tex]\pi[/tex] × r² × [tex]\frac{\Theta }{360^{\circ}}[/tex]Or, Area of sector = [tex]\pi[/tex] × 42 × [tex]\frac{\60° }{360^{\circ}}[/tex]or, Area of sector = [tex]\pi[/tex] × 42 × [tex]\frac{1}{6}[/tex]∴ Area of sector = [tex]\pi[/tex] × 7I.e Area of sector = 7 [tex]\pi[/tex] m²Hence The Area of sector is 7 [tex]\pi[/tex] m² . Answer