Find the distance between the points given. (-3, 0) and (0, √7) √2 4 √(13)

Answer:4Step-by-step explanation:To solve this we are using the distance formula:[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]where[tex](x_1,y_1)[/tex] are the coordinates of the first point [tex](x_2,y_2)[/tex] are the coordinates of the second point We know that the first point is (2, –6), so [tex]x_1=-3[/tex] and [tex]y_1=0[/tex]. The second point is (0, √7), so [tex]x_2=0[/tex] and [tex]y_2=\sqrt{7}[/tex]. Let's replace the values in our formula to find the distance between the points: [tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex][tex]d=\sqrt{(0--3)^2+(\sqrt{7}-0)^2 }[/tex][tex]d=\sqrt{(3)^2+(\sqrt{7})^2 }[/tex][tex]d=\sqrt{9+7}[/tex][tex]d=\sqrt{16}[/tex][tex]d=4[/tex]We can conclude that the distance between (-3, 0) and (0, √7)  is 4.